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(13) 5 bars Chebyshev Leg (best)Now restriction: When P (target,slidable) position is in left side of D position, Q' (2nd leg) trace tells a lie. Pardon me.
Fumio Imai, 2014/04/28, Created with GeoGebra |
(13-a) 5 bars Chebyshev Leg (small span)This is the material for Understanding the mechanism of 5 bars Leg, and tuning application of its bar size estimation.Drag the red bullet ● Crank. Leg frame moving is as if a human walking. --- It's interesting to see. i.e. The man who is walking on the Belt conveyor.
Fumio Imai, 2014/04/28, Created with GeoGebra |
(13-b) 5 bars Chebyshev Leg (big span)
Fumio Imai, 2014/04/28, Created with GeoGebra |
(13-c) 5 bars Chebyshev Leg (quasi-linear)
Fumio Imai, 2014/04/30, Created with GeoGebra |
(13-d) Variety of output (big type, circle slider)Like a Klann Leg shape, but the same crank rotation direction.
Fumio Imai, 2014/05/03, Created with GeoGebra |
(13-e) Imai's linkage (alias, Crescent mapping leg)Green curve, what is this?, where, point N = middle of segment IJ, length of NQ = 0.5 IJ. c. FJ=6.41 is better. 0.5(arm4 + FJ) radius draws the circle in the complele middle of crescent moon. so, arm4 < FJ is true. ----- latest information; FJ = 6.00 is better than 6.41 I think " this works is ART.", don't you think so?c. long = 2, M = (-0.53, 9.51) case, pink trace is almost the same as the long = ∞ case (violet color trace). i.e. long is not necessary long. short is OK. ------ why? this is able to explain theoretically. --- See, my parent material. "(quasi) Vertical straight line slider doesn't need long long bar."
Fumio Imai, 2014/05/04, Created with GeoGebra |
(13-f) Imai's Linkage equivalent frame
Fumio Imai, 2014/05/27, Created with GeoGebra |
(13-g) Imai's linkage (tri-pedal) (alias: walking easel)I want to locate the point C to (-1, 0) by mouse dragging. but I couldn't/ failed.Can't set precise position. How to? GeoGebra is foolish. Alternately, define T=0 to 2 pi (and specify slider function), and, C = (cos(T), sin(T)) , then slide T. trace is discrete type. At last, by input box, Type "T=pi". --- if necessary please do.
Fumio Imai, 2014/05/30, Created with GeoGebra |
(13-h) Imai's linkage ( arm3, arm4 rule )
Fumio Imai, 2014/06/11, Created with GeoGebra |
(13-i) Imai's Linkage (bi-pedal with foot)
Fumio Imai, 2014/06/12, Created with GeoGebra |
(13-j) Imai's Watt's linkage Leg (3 bars/ leg)subtitle: -- Why exists Arches of the foot? --Number slider: leg ---- C'F' length. leg' ---- C'I length. Point F'', tF, B▲ (circle center) is slidable. tF is large circle tangent point. I'' is mirror point of I', tF' is it's middle point. Pink arc I'-tF-I'' is made by Circumcircular Arc through Three Points function. this Arc radius size is calclated by rr = (I'tF)2/(2tFtF'). Now, Point A'' (straight foward stroke end crank angle point) is fixed by Object Properties function specifying " ☑ Fix Object", so if you want to move A'' , remove this specifying mark ✓.
Fumio Imai, 2014/06/16, Created with GeoGebra |
(13-k) Imai's Watt's linkage Leg walking Toy on the slope
Fumio Imai, 2014/06/16, Created with GeoGebra |
(13-l) Imai's Watt's linkage Vertical Leg (5 bars/ leg)Please check, B = (0, 1.64) [ or B(-1.64, 0) ] case ------ This is Chebyshev linkage case.(Chebyshev linkage and Watt's linkage are the same family.)
Fumio Imai, 2014/06/20, Created with GeoGebra |
(13-m) Imai's Watt's linkage Vertical Leg (180° cycle)
Fumio Imai, 2014/06/24, Created with GeoGebra |
(13-n) Imai's Watt's linkage Leg (180 deg cycle) JudgePlease try: r=3, u=1, ε = 0.1, XC = 12.84This shape is allowable. more symmetric form. ( Please consider the meaning of U, U' position. )
Fumio Imai, 2014/06/25, Created with GeoGebra |
(13-o) Imai's Watt's Linkage curve
Fumio Imai, 2014/06/29, Created with GeoGebra |
(14) Imai's Inversor LegI think + 2 bars method is so simple, so good.
Fumio Imai, 2014/05/13, Created with GeoGebra |
(14-a) Imai's Inversor +2 Leg
Fumio Imai, 2014/05/18, Created with GeoGebra |
(14-b) Imai's Inversor out-crank Leg
Fumio Imai, 2014/05/20, Created with GeoGebra |
(14-c) Imai's hiccup sector Leg
Fumio Imai, 2014/06/02, Created with GeoGebra |
(14-d) Hart's Inversor DEMOFor your reference: This information is a review. Q: What is Hart's Inversor ? --------- A: See below my DEMO. qq is internal division point/ external division point RATIO. qq > 1 is OK, too. i.e. External division. (In general, 0 < qq < 1, is well known. but qq > 1 is OK, and this is better /more useful than qq < 1 case. The shape of qq > 1 case is near the shape of manipulator/ arm/ leg. --- is not a inner point, but end-point node. So, not crowded space. no nuisance bars.) This DEMO was brought from below URL java applet. http://www5d.biglobe.ne.jp/~the_imai/etymology/G_A-frame.html
Fumio Imai, 2014/01/29, Created with GeoGebra |
(14-e) Hart's A-frame hiccup leg sample
Fumio Imai, 2014/06/07, Created with GeoGebra |